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算法系列15天速成——第十五天 图【下】(大结局)

发布时间:2020-03-14 19:11:41 所属栏目:安全 来源:站长网
导读:今天是大结局,说下“图”的最后一点东西,“最小生成树“和”最短路径“

//将取得的最小节点标识为已访问
                weight[index] = short.MaxValue;
                tempvertex[index] = 0;

//从最新的节点出发,将此节点的weight比较赋值
                for (int j = 0; j < graph.vertexNum; j++)
                {
                    //已当前节点为出发点,重新选择最小边
                    if (graph.edges[index, j] < weight[j] && tempvertex[j] != used)
                    {
                        weight[j] = graph.edges[index, j];

//这里做的目的将较短的边覆盖点上一个节点的邻接点中的较长的边
                        tempvertex[j] = int.Parse(graph.vertex[index]);
                    }
                }
            }
        }
        #endregion

#region dijkstra求出最短路径
        /// <summary>
/// dijkstra求出最短路径
/// </summary>
/// <param></param>
        public void Dijkstra(MatrixGraph g)
        {
            int[] weight = new int[g.vertexNum];

int[] path = new int[g.vertexNum];

int[] tempvertex = new int[g.vertexNum];

Console.WriteLine("n请输入源点的编号:");

//让用户输入要遍历的起始点
            int vertex = int.Parse(Console.ReadLine()) - 1;

for (int i = 0; i < g.vertexNum; i++)
            {
                //初始赋权值
                weight[i] = g.edges[vertex, i];

if (weight[i] < short.MaxValue && weight[i] > 0)
                    path[i] = vertex;

tempvertex[i] = 0;
            }

tempvertex[vertex] = 1;
            weight[vertex] = 0;

for (int i = 0; i < g.vertexNum; i++)
            {
                int min = short.MaxValue;

int index = vertex;

for (int j = 0; j < g.vertexNum; j++)
                {
                    //顶点的权值中找出最小的
                    if (tempvertex[j] == 0 && weight[j] < min)
                    {
                        min = weight[j];
                        index = j;
                    }
                }

tempvertex[index] = 1;

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