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算法系列15天速成——第十三天 树操作【下】

发布时间:2020-03-14 19:11:13 所属栏目:安全 来源:站长网
导读:今天说下最后一种树,大家可否知道,文件压缩程序里面的核心结构,核心算法是什么?或许你知道,他就运用了赫夫曼树

//四个叶子节点的循环
            for (int i = 0; i < leafNum; i++)
            {
                //单个字符的编码串
                string codeTemp = string.Empty;

current = i;

//第一次获取最左节点
                parent = huffman[current].parent;

while (parent != 0)
                {
                    //如果父节点的左子树等于当前节点就标记为0
                    if (current == huffman[parent].left)
                        codeTemp += "0";
                    else
                        codeTemp += "1";

current = parent;
                    parent = huffman[parent].parent;
                }

huffmanCode[i] = new string(codeTemp.Reverse().ToArray());
            }
            return huffmanCode;
        }
        #endregion

#region 对指定字符进行压缩
        /// <summary>
/// 对指定字符进行压缩
/// </summary>
/// <param></param>
/// <param></param>
/// <param></param>
        public string Encode(string[] huffmanCode, string[] alphabet, string test)
        {
            //返回的0,1代码
            string encodeStr = string.Empty;

//对每个字符进行编码
            for (int i = 0; i < test.Length; i++)
            {
                //在模版里面查找
                for (int j = 0; j < alphabet.Length; j++)
                {
                    if (test[i].ToString() == alphabet[j])
                    {
                        encodeStr += huffmanCode[j];
                    }
                }
            }

return encodeStr;
        }
        #endregion

#region 对指定的二进制进行解压
        /// <summary>
/// 对指定的二进制进行解压
/// </summary>
/// <param></param>
/// <param></param>
/// <param></param>
/// <param></param>
/// <returns></returns>
        public string Decode(HuffmanTree[] huffman, int huffmanNodes, string[] alphabet, string test)
        {
            string decodeStr = string.Empty;

//所有要解码的字符
            for (int i = 0; i < test.Length; )
            {
                int j = 0;
                //赫夫曼树结构模板(用于循环的解码单个字符)
                for (j = huffmanNodes - 1; (huffman[j].left != 0 || huffman[j].right != 0); )
                {
                    if (test[i].ToString() == "0")
                    {
                        j = huffman[j].left;
                    }
                    if (test[i].ToString() == "1")
                    {
                        j = huffman[j].right;
                    }
                    i++;
                }
                decodeStr += alphabet[j];
            }
            return decodeStr;
        }

#endregion
    }
}

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